This is with reference to my earlier blog where the dimensions of a box are x y and z and these satisfy 3 equations and I wanted you to find the volume of the box.
Multiplying both the right and left hand sides of the 3 equations we get
xyz+x+y+z+1/x+1/y+1/z+1/xyz=4*7/3*1=28/3
But adding both sides of the equations we get x+1/x+y+1/y+z+1/z=4+7/3+1=22/3
Deducting result 2 from result1 we get xyz+1/xyz=2
This will be possible only when xyz=1 and so xyz the volume of the box is 1
Multiplying both the right and left hand sides of the 3 equations we get
xyz+x+y+z+1/x+1/y+1/z+1/xyz=4*7/3*1=28/3
But adding both sides of the equations we get x+1/x+y+1/y+z+1/z=4+7/3+1=22/3
Deducting result 2 from result1 we get xyz+1/xyz=2
This will be possible only when xyz=1 and so xyz the volume of the box is 1
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