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Friday, 30 March 2012

Right and left

The number 21978 is formed out of the 5 digits 2,1,9,7 and 8
If the digits are taken from right to left ,the number formed will be 87912
You will find that 87912 is four times 21978.
Such numbers are not definitely very easy to find. 

Saturday, 24 March 2012

Reverse a magic square-Corrigendum

There was a small mistake in my previous blog-The actual position is as follows-
There are 3 magic squares,formed with the numbers 11,16,18,19,61,66,68,69,81,86,88,89
91,96,98,99
First is the normal one,Second one formed by reversing or inverting the first,the third is formed by rotating the first by 90 degrees.All three give the same total 264 all around.They are shown below-
96,11,89,68
88,69,91,16
61,86,18,99
19,98,66,81
Second one-
16,68,99,81
91,89,18,66
88,96,61,19
69,11,86,98
Third one-
18,99,86,61
66,81,98,19
91,16,69,88
89,68,11,96

Friday, 23 March 2012

Reverse a magic square

I  show below a magic square with totals 264 all around-
96,11,89,68
88,69,91,16
61,86,18,99
19,98,66,81
Now reverse the grid.,and make a small change,you will get a new magic square having the same totals all around-
18,99,86,61
66,81,98,19
91,16,69,88
89,68,11,96

Friday, 16 March 2012

Inflation number 72

This is an issue involving inflation.
Suppose you find that the cost of a product or service uniformly goes up every year by 10%.
Will you be able to find out when the cost or service becomes double?
The answer is 7.2 years,the period 7.2 being one tenth of 72.
If the cost goes up every year by 5%,the period will be 14.4 years,the same being one-fifth of 72
Using the number 72,you can find the period for any percentage of increase.
Will you be able to work out how this number 72 is involved?.

Friday, 9 March 2012

Repeating sequence

I am giving below a few initial terms of a sequence-
0,0,0,1,0,2,1,0,3,2,1,4,0,5,3,,2,6,1,7,4,0,8,5.........
The surprising feature of this sequence is that if  you delete the first occurrence of each digit,the original sequence will show up again.
I am showing below the position after deleting the first occurrence of each digit  ,the  deleted digits shown in brackets for ready check-
(0),0,0,(1),0,(2),1,0,(3),2,1,(4),0,(5),3,2,(6),1,(7),4,0,(8),5.....
Can you find out the further digits/numbers in the original sequence so that this property remains in force?