The dimensions of a rectangular cuboid box are x ,y and z. They satisfy the following equations-
x+(1/y)=4....y+(1/z)=1....z+(1/x)=7/3.
Find the volume of the box
This refers to my previous blog wherein I had posted a question-From a container containing a syrup-water mixture in the ratio 5/3,how much should be removed and replaced by an equal quantity of water so that the syrup and water are contained equally
If the syrup content is to be changed from 5/8 to 1/2 we have to remove 1/8 content of syrup which will need 1/5 of the total mixture--{5/8}-{(1/5)*(5/8)}=5/8-1/8=1/2.
The water content then will become 3/8-(1/5ths of 3/8)+1/5=3/8-3/40+1/5= that is (15-3+8)/40=20/40=1/2 as required.
Other variations ratio 5/7..1/7ths of the mixture to be replaced
5/9..2/9 ths of the mixture to be replaced
5/11..3/11 ths of the mixture to be replaced as follows
syrup 7/12-1/7 ths of 7/12=1/2 ..water 5/12-(5/12*1/7)+1/7=(35-5+12)/84=42/84=1/2
9/14-2/9 ths of 9/14=1/2 5/14-(5/14*2/9)+2/9=(45-10+28)/126=63/126=1/2
11/16-3/11ths of 11/16=1/2 5/16-(5/16*3/11)+3/11=(55-15+48)/176=88/176=1/2
A vessel contains a liquid 3 parts of which are water and 5 parts syrup.How much of the liquid must be drawn off and replaced with water so that the liquid may be half water and half syrup?
Alternately if the original liquid contains 5 parts water and 7 parts syrup?.
This is a rejoinder to my blog posted on 11 june.-reproduced below-
A sequence of numbers a(1),a(2),a(3)......a(100) has the property that for every integer k between 1 and k inclusive the number a(k) is k less than the sum of the other 99 numbers.Find the 50th number-
There has been no response so far.
The solution can be arrived at as follows-
If S is the sum of the 100 numbers,a(k)=S-a(k)-k.
So 2a(k)=S-k
Substituting the values 1 to 100 for k in this equation and adding all the results we will have
2S=100S-(the sum of the 100 numbers from 1 to 100) or
98S=5050 or S= 5050/98.
So a(50)=(5050/98)-a(50)-50
or 2a(50)=(5050/98)-50=150/98
or a(50)=75/98
A sequence of numbers a1,a2,a3,....... a100 has the property that for every integer k between 1 and k inclusive,the number ak is k less than the sum of the other 99 numbers.Find the 50th number of the sequence.
A person chooses a 3 digit number of the form N=ABC where A,B,C are distinct digits.He then considered all possible numbers of the form ACB,BCA,BAC,CAB and CBA.He then added these 5 numbers and got the result 3194.Determine the number N
There has been no response so far.
However the solution can be arrived at as follows-
If there were 63 pages in the book,the sum of the page numbers from 1 to 63 will be 2016.
As the addition of an extra page number gave the total 2014,the total number of pages could not be 63 but 62.
For 62 pages the sum of the page numbers will be 1953 and so the page number added wrongly should be 2014-1953=61.
Here is a puzzle regarding security code-
Before the entry gate of a secured post,the security guard will give a password to the person wishing to enter.The person has to give a reply.Only if the reply is correct he will be allowed to enter.
Person A comes to the gate.The guard mentions the number 12,A gives the answer 6. He is allowed to enter.
Person B comes to the gate-The guard mentions 6.B gives the answer 3.He is allowed to enter.
Person C comes to the gate after seeing the previous 2 persons entering.The guard mentions 8.C gives the reply 4.He is not allowed inside.
Can you make out why?
The code followed is this-When the guard gives a number,the person wishing to enter should find out the number of alphabets required for writing out the number and give it as the answer-6 letters for 12 and 3 letters for 6. You can see that for the number 8,it should be 5 instead of 4 due to which C was not allowed inside.